M Karim Physics Numerical Book Solution Class 11 · Essential & Working

$$10 = \mu \times 5 \times 9.8$$

A block of mass 5 kg is placed on a horizontal surface. A force of 20 N is applied to the block, causing it to move with a uniform acceleration of 2 m/s². What is the coefficient of friction between the block and the surface? m karim physics numerical book solution class 11

Given: $v = 20$ m/s, $u = 0$ m/s, $t = 5$ s $$10 = \mu \times 5 \times 9

$$\mu = \frac{10}{5 \times 9.8} = 0.2$$